Question

Does (x-1)(x+2)+2=0 have a real root?

Answer 1

$= > (x - 1)(x + 2) + 2 = 0 \\ \\ = > {x}^{2} + 2x - x - 2 + 2 = 0 \\ \\ = > {x}^{2} + x = 0 \\ \\ = > x(x + 1) = 0 \\ \\ = > x + 1 = 0 \\ \\ = > x = - 1 \\ \\ so \: x \: have \: real \: root.$

Answer 2

Hi Friend !!!

Here is ur answer !!

(x-1)(x+2)+2 = 0

x² -2 -x +2x+2 = 0

x² +x = 0

x(x+1) = 0

x= 0 , x+1 = 0

x = 0 , -1

So, it has real roots

Hope it helps u : )