What is the ratio of molarity to normatily for H2SO3 solution?
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Hey.
Here is the answer.
The 'Normality' of a solution is the 'Molarity' multiplied by the number of equivalents per mole.
So, no. of equivalents per mole of H2SO3 with base will be 2N.
A 1 M solution of H2SO3 will contain only one mole of H2SO3 in 1 liter of solution, but if the solution is titrated with a base, it will be shown to contain two moles of acid. This is because a single molecule of H2SO3contains two acidic protons (H+ Ions). Thus, a 1 M solution of H2SO3 will be 2 N.
So, Ratio of molarity to normality will be 1M/2N
= 1 : 2.
Thanks .
Here is the answer.
The 'Normality' of a solution is the 'Molarity' multiplied by the number of equivalents per mole.
So, no. of equivalents per mole of H2SO3 with base will be 2N.
A 1 M solution of H2SO3 will contain only one mole of H2SO3 in 1 liter of solution, but if the solution is titrated with a base, it will be shown to contain two moles of acid. This is because a single molecule of H2SO3contains two acidic protons (H+ Ions). Thus, a 1 M solution of H2SO3 will be 2 N.
So, Ratio of molarity to normality will be 1M/2N
= 1 : 2.
Thanks .
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