doing some work Ganesh takes 10 days more than 1 together they complete the work in 12 days
Answers
Answer:
if he work alone.
Step-by-step explanation:
Consider the provided information.
Let Gajanan takes x days.
Ganesh takes 10 days more than Gajanan: x+10
Together they complete the work in 12 days.
This can be written as:
\frac{1}{x} +\frac{1}{x+10}=\frac{1}{12}
x
1
+
x+10
1
=
12
1
\frac{x+10+x}{x(x+10)}=\frac{1}{12}
x(x+10)
x+10+x
=
12
1
\frac{10+2x}{x^2+10x}=\frac{1}{12}
x
2
+10x
10+2x
=
12
1
120+24x=x^2+10x120+24x=x
2
+10x
x^2-14x-120=0x
2
−14x−120=0
x^2-20x+6x-120=0x
2
−20x+6x−120=0
x(x-20)+6(x-20)=0x(x−20)+6(x−20)=0
(x-20)(x-6)=0(x−20)(x−6)=0
x=20\ or\ x=-6x=20 or x=−6
Number of days can't be a negative number so the value of x is 20.
Thus, Gajanan takes 20 days.
Ganesh takes 10 days more than Gajanan i.e 30 days.
#learn more
For doing some work Ganesh takes 10 days more than John.If both work together they will complete the work in 12 days.Find the number of days required to complete the work if they work alone.if he work alone.
Step-by-step explanation:
Consider the provided information.
Let Gajanan takes x days.
Ganesh takes 10 days more than Gajanan: x+10
Together they complete the work in 12 days.
This can be written as:
\frac{1}{x} +\frac{1}{x+10}=\frac{1}{12}
x
1
+
x+10
1
=
12
1
\frac{x+10+x}{x(x+10)}=\frac{1}{12}
x(x+10)
x+10+x
=
12
1
\frac{10+2x}{x^2+10x}=\frac{1}{12}
x
2
+10x
10+2x
=
12
1
120+24x=x^2+10x120+24x=x
2
+10x
x^2-14x-120=0x
2
−14x−120=0
x^2-20x+6x-120=0x
2
−20x+6x−120=0
x(x-20)+6(x-20)=0x(x−20)+6(x−20)=0
(x-20)(x-6)=0(x−20)(x−6)=0
x=20\ or\ x=-6x=20 or x=−6
Number of days can't be a negative number so the value of x is 20.
Thus, Gajanan takes 20 days.
Ganesh takes 10 days more than Gajanan i.e 30 days.
#learn more
For doing some work Ganesh takes 10 days more than John.If both work together they will complete the work in 12 days.Find the number of days required to complete the work if they work alone.