dolve question no. 10
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log2 x=a
2^a=x
log3 y=a
3^a=y
72^a=(8*9)^a
=(2^3*3^2)^a
=2^3a*3^2a
=(2^a)^3*(3^a)^2
=x^2*y^3
2^a=x
log3 y=a
3^a=y
72^a=(8*9)^a
=(2^3*3^2)^a
=2^3a*3^2a
=(2^a)^3*(3^a)^2
=x^2*y^3
Answered by
1
Hi ,
log ( base 2 ) x = a
2^a = x ---( 1 )
log ( base 3 ) = a
3^a = y -- ( 2 )
Now ,
72^a
= ( 2³ × 3² )^a
= 2^3a × 3^2a
= ( 2^a )³ × ( 3^a )²
= x³y² [ from ( 1 ) and ( 2 ) ]
I hope this helps you .
: )
log ( base 2 ) x = a
2^a = x ---( 1 )
log ( base 3 ) = a
3^a = y -- ( 2 )
Now ,
72^a
= ( 2³ × 3² )^a
= 2^3a × 3^2a
= ( 2^a )³ × ( 3^a )²
= x³y² [ from ( 1 ) and ( 2 ) ]
I hope this helps you .
: )
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