Question

dolve question no. 10

Answer 1

log2 x=a
2^a=x
log3 y=a
3^a=y
72^a=(8*9)^a
=(2^3*3^2)^a
=2^3a*3^2a
=(2^a)^3*(3^a)^2
=x^2*y^3

Answer 2

Hi ,

log ( base 2 ) x = a

2^a = x ---( 1 )

log ( base 3 ) = a

3^a = y -- ( 2 )

Now ,

72^a

= ( 2³ × 3² )^a

= 2^3a × 3^2a

= ( 2^a )³ × ( 3^a )²

= x³y² [ from ( 1 ) and ( 2 ) ]

I hope this helps you .

: )