When a particle is moving along y axis it's position varies with time as Y=t^2-3t+1 where Y is in meters and t is in second what is the distance travelled by the particle in first 2 seconds
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Distance at t=0 is 1 metre..
now if we differentiate the above equation .
we get
v=2t-3
put v= o
then t=1.5 sec..
so it is obvious that the particle changes its direction after 1.5seconds of its journey..
then displacement travelled at t=1.5=3/2second is
3.25-4.5= - 1.25 metre....
displacement in 2 seconds=-1 metre.
then total distance covered=2.25+.25=2.5metre
now if we differentiate the above equation .
we get
v=2t-3
put v= o
then t=1.5 sec..
so it is obvious that the particle changes its direction after 1.5seconds of its journey..
then displacement travelled at t=1.5=3/2second is
3.25-4.5= - 1.25 metre....
displacement in 2 seconds=-1 metre.
then total distance covered=2.25+.25=2.5metre
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