Question

domain of 1/x^2-x-6​

Answer 1

Answer:

R - { -2, 3 }

Step-by-step explanation:

f(x) = 1/x^2-x-6

= 1/(x - 3)(x + 2)

hence f(x) is not defined at x = 3 & -2

therefore Range [ f(x) ] = R - { -2, 3 }

Answer 2

Answer:

hope this will help you