domain of function f(x)=(3x+5)/(5x+4)
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1
Answer:
3x,5x
Step-by-step explanation:
the first element of ordered pair are known as foaming
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0
Answer:
f(x) = (x^2 +3x+5)/(x^2 -5x+4) which is well defined every where except the points where denominator of f(x) becomes 0 and these points are given by x^2 -5x + 4 = 0 or (x-4)(x-1) = 0 ==> x = 4 , 1 . Note that at these two points numerator of
f(x) is not zero. Hence domain of f that is D(f) = R - {1, 4 }
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