Question

Domain of the function 1/6x-x^2-5

Answer 1

Step-by-step explanation:

given,

f(x)=1/6x-x^2-5

therefore,

6x-x^2-5≠0

x^2-6x+5≠0

x^2-x-5x+5≠0

x(x-1)-5(x-1)≠0

(x-5)(x-1)≠0

x≠1,5

domain is R-{1,5}

Answer 2

Step-by-step explanation:

$\frac{1}{6x} - {x}^{2} - 5$

$6x - {x}^{2} - 5 \: unequal \: to \: 0$

${x}^{2} - 6x + 5$

${x}^{2} - x - 5x + 5$

$x(x - 1) - 5(x - 1)$

$(x - 1)(x - 5)unequal \: to \: 0$

$x \: is \: unequal \: to \: 1 \: and \: 5$

$domoin \: r \: = 1 \: and \: 5$