Dome of a building is in the form of hemisphere . From inside it is whitewashed at rupees 498.96 . If the cost of whitewashing is rupees 2 per metre square ,
(i) find the inside surface area of the dome.
(ii) volume of the air inside the dome.
Answers
Answered by
23
I) LSA of dome = 498.96/2= 249.48 sq. m
LSA= 2 pi r^2
=> 498.48 = 2 x 3.14 x r^2
=> 498.48/ 6.28= r^2
r = √79.37 = 9 (approx)
II) [volume of hemisphere= 2/3 pi r ^3]
=> 2/3 x 3.14 x 9 x 9 x 9
=>1526.04 cubic m.
LSA= 2 pi r^2
=> 498.48 = 2 x 3.14 x r^2
=> 498.48/ 6.28= r^2
r = √79.37 = 9 (approx)
II) [volume of hemisphere= 2/3 pi r ^3]
=> 2/3 x 3.14 x 9 x 9 x 9
=>1526.04 cubic m.
boredtroye561995:
Thank you so much!
my pleasure
my pleasure
:-)
Similar questions