Question

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Answer 1

Given:-

• Initial pressure of air in tyre,P₁= 1.5 atm
• Final pressure of air in tyre,P₂= 1.75 atm
• Initial temperature of air in tyre,T₁= 300 K

To Find:-

• Final temperature of air

Solution:-

According to equation of Ideal gas,

$\pink{\underline{\boxed{\bf{PV=nRT}}}}$

where,

• P is pressure
• V is volume
• n is no. of moles
• R is gas constant
• T is temperature

If volume, temperature and same amount of gas is taken then

$\purple{\underline{\boxed{\bf{\dfrac{P}{T}=constant}}}}$

or

$\orange{\underline{\boxed{\bf{\dfrac{P_{1}}{T_{1}}=\dfrac{P_{2}}{T_{2}}}}}}$

where,

• P₁ initial pressure
• T₁ is initial temperature
• P₂ is final pressure
• T₂ is final temperature

━━━━━━━━━━━━━━━━━━━━━━━━━

Let the final temperature be T₂

So,

$\longrightarrow\rm{\dfrac{P_{1}}{T_{1}}=\dfrac{P_{2}}{T_{2}}}$

$\longrightarrow\rm{\dfrac{1.5}{300}=\dfrac{1.75}{T_{2}}}$

$\longrightarrow\rm{T_{2}=\dfrac{1.75\times300}{1.5}}$

$\longrightarrow\rm\green{T_{2}=350^{\circ}C}$

Hence, the final temperature is 350°C.

Answer 2

Answer:

Refer to the attachment

hence the answer will be 350 K