Question

don't spam it post correct answer​

Answer 1

★Given:-

• Amount invested = Rs. 13,900
• It is divided in two different schemes A and B.

• Simple interest rate = 14% p.a. and 11% p.a. respectively.

• Total amount of simple interest earned in 2 years= Rs. 3508

★To find:-

• Amount invested in scheme B.

★Solution:-

Let the amount invested in Scheme A =Rs.x

And given,total amount invested = Rs.13900

Then,

Amount invested in scheme B =Rs.(13900-x)

We know:

$\leadsto \sf SI=\frac{PRT}{100}$

Where,

SI = simple interest

R = rate

T = time

Case - 1:-

P = x

R = 14

T = 2

Putting the values in the formula,

$\displaystyle :\implies \sf SI = \frac{x\times 14\times 2}{100} \\\\\\:\implies \sf SI = \frac{28x}{100}.......(1)$

Case-2:-

P = 13900-x

R = 11

T = 2

Putting values,

$\displaystyle :\implies \sf SI=\frac{(13900-x)\times 11\times 2 }{100} \\\\\\:\implies \sf SI = \frac{22(13900-x)}{100}.........(2)$

Now,

Given,

• Total interest = Rs.3508

Equation (1)+(2) gives the total interest

$\displaystyle :\implies \sf \frac{28x}{100} +\frac{22(13900-x)}{100} = 3508\\\\\\:\implies \sf 28x + 22(13900-x) = 3508 \times 100 \\\\\\:\implies \sf 28x+305800-22x= 350800\\\\\\:\implies \sf 6x = 45000\\\\\\:\implies \sf x=\frac{45000}{6} \\\\\\:\implies \bold{x=7500.}$

We have,

Amount invested in scheme B = 13900 - x

Putting value of x,

$:\implies \sf A=13900-7500\\\\:\implies \underline{\boxed{\bold{Amount = Rs.6400.}}}$

Hence,

The amount invested in scheme B is Rs.6400.

_________________

Answer 2

Given :  Invested Amount  Rs 13900 divided in 2 different schemes A and B at SI 14% pa and 11% pa

Total amount of SI earned in 2years = 3058

To Find : Amount invested in Scheme B

Solution:

Let say Amount invested in Scheme B  = 100P

Amount invested in Scheme A  = 13900 - 100P

= 100(139 - P)

SI = P x R x T /100

invested in Scheme A  =100(139 - P)

R = 14%

T = 2

SI = 100(139 - P) * 14 * 2 /100

= (139 - P)28

= 3892 - 28P

invested in Scheme B  =100P

R = 11%

T = 2

SI = 100P  * 11 * 2 /100

=22P

3892 - 28P + 22P =  3508

=> 3892 - 6P =  3508

=> 6P =  384

=> P = 64

=> 100P = 6400

Amount invested in Scheme B = Rs 6400

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