Question

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1) A number is twice another number. If their sum is 96 ,what are the numbers. ( )
a) 36, and 60
b) 45 and 51
c) 32 and 64
d) 16 and ,80

2). Solve x/2 -×/3 = 1 ( )
a) 1
b) -1
c) 6
d) -6

3).. Raju's present age is twice the age of four years ago. Find his present age ...
a) 6 years
b) 4 years
c) 8 Years
d) 10 years​

Answer 1

Answer:

1)     c) 32 and 64

2)    c) 6

3)    c) 8 Years

Step-by-step explanation:

1) let x and y be the numbers.

Given that x = 2y ----------- (1)

and x + y = 96

=> 2y + y = 96

=> 3y = 96

=> y = 96/3 = 32

substitute y=32 in (1), we get, x = 2(32) = 64

x=64;y=32

2) (x/2) - (x/3) = 1

    x( 1/2 - 1/3) = 1

=> x ((3-2)/6) = 1

=> x (1/6) = 1

=> x = 1*6 = 6

3) let rajus present age be x,

given that x= 2(x-4)

=> x =2x-8

=> 2x-x = 8

=> x=8

Answer 2

Answer:

for first

let those 2 no. be x ans 2x respectively

so, x + 2x = 96

3x = 96

x = 96/3

x = 32

option c

for second

x/2 - x/3

lcm of 2,3= 6

3(x)/3(2) - 2(x)/2(3) = 1

3x/6 - 2x/6 = 1

x/6 = 1

x = 6*1

x= 6

option c

for third

let raju's present age be x

so his age 4 years ago was 2x

so, 2x = x-4

2x-x = 4

x = 4

option b