Math, asked by thmanchester26, 1 year ago

donna, chris, and austin have total of $93 in their wallets. donna has $7 more than chris. austin has 3 times what donna has. how much do they have in their wallets?

Answers

Answered by ratdna
2

Let Chris have x dollars.

Then, Donna has $7 + x

Austin has 3($7 + x)

= $21 + 3x

Now, the sum of the money each has is $93.

= x + (7+x) + (21 + 3x) = 93

= 5x + 29 = 93

= 5x = 93 - 29 = 64

= 5x = 64

= x = 64/5 = $12.8

Henceforth, Chris has $12.8

Donna has $19.8

and Austin has $59.4

Answered by ankita9126
0

Answer:

let dona=x

chris=y

austin=z

then atq

x+y+z=93

x=y+7

z=3(y+7)

then,

y+(y+7)+3(y+7)=93

y+7+y+3y+21=93

5y+28=93

5y=65

y=13

x=20

z=69

so , donna have $20

chris have$13

austin have $69

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