Question

donno,, maybe in the hell, i was not in mood to talk with anyone
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a moving car along a straight line highway with speed of 126/hrs brought to a stop within a distance of 200 m. What is the retardation of the car (assumed uniform), and how long does it take for the car to stop​​

Answer 1

first convert 126kmph to m/s ie. 35 m/s.

v^2 - u^2 = 2as

a= acceleration or retardation

v= final velocity =0

u= initial velocity = 35m/s

s= displacement = 200m

0–35^2 = 2a*200 ==> a= -35^2/400 = -1225/400

a= -3.0625m/s^2 is the retardation

Now, v= u +at where t is the time taken

0 = 35 + (-3.0625)t

t= 35/3.0625 = 11.43 seconds approx.

Answer 2

Answer:

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Explanation:

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