Question

find zeroes of 6xsquare -3-7x​

Answer 1

Equate the given p(x) = 0. ⇒ 6x² - 3 = 0. Dividing each term of the equation by 3. ⇒ 2x² - 1 = 0. ⇒ 2x² = 1. ⇒ x² = 1/2. ...

⇒ α = 1/2 and β = -1/2. Now, α = 1/2. -b/a = -(-3)/6. ⇒ -b/a = 1/2.

So, α = -b/a. And, β = -1/2.

So, β = b/a.

Answer 2

Answer:

6x^2-7x-3=0

6x^2-9x+2x-3=0

3x(2x-3)+1(2x-3)=0

x=-1 and 3/2