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Why the number 4n
, where n is a natural number, is not divisible by 5?
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For the number 4n to end with digit zero for any natural number n, it should be divisible by 5. ... But it is not possible because 4n=(2)2n so 2 is the only prime in the factorisation of 4n. Since 5 is not present in the prime factorization, so there is no natural number n for which 4n ends with the digit zero
Step-by-step explanation:
factorization is the main reason
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