Double displacement reaction does not take place when NaNO3 and KCl are mixed together. Give reasons.
Answers
Answered by
3
cause na is less reactive than potassium (k)
johnysingh:
thanks
wels
Answered by
3
Double displacement reaction does not take place when an aqueous solution of NaNO3 and KCl are mixed? Why?
Still have a question? Ask your own!
What is your question?
Ad by Blinkist
Ever read 4 books in one day? Try the Blinkist app.
Read or listen to the world's best nonfiction books in a matter of minutes and become a smarter you.
Get the App
1 ANSWER

Boris Bartlog, machinist, mechanical designer, software engineer
Answered Mar 1 · Author has 1.2k answers and1.4m answer views
At commonly used concentrations and ordinary temperatures, there is nothing that would remove one of the products from solution. All you have is an aqueous solution containing all the ions from both salts. And if the solution is allowed to evaporate at anything resembling a normal temperature, the first salt to precipitate will be KCl once again.
If you were able to boil the resulting solution at a temperature significantly above the normal boiling point of water (maybe some kind of pressurized container that allowed you to gradually boil off water at 140C and 4 atmospheres pressure), you could probably get NaCl to precipitate first, leaving KNO3 in solution; its solubility increases very little with temperature while KCl becomes significantly more soluble.
Still have a question? Ask your own!
What is your question?
Ad by Blinkist
Ever read 4 books in one day? Try the Blinkist app.
Read or listen to the world's best nonfiction books in a matter of minutes and become a smarter you.
Get the App
1 ANSWER

Boris Bartlog, machinist, mechanical designer, software engineer
Answered Mar 1 · Author has 1.2k answers and1.4m answer views
At commonly used concentrations and ordinary temperatures, there is nothing that would remove one of the products from solution. All you have is an aqueous solution containing all the ions from both salts. And if the solution is allowed to evaporate at anything resembling a normal temperature, the first salt to precipitate will be KCl once again.
If you were able to boil the resulting solution at a temperature significantly above the normal boiling point of water (maybe some kind of pressurized container that allowed you to gradually boil off water at 140C and 4 atmospheres pressure), you could probably get NaCl to precipitate first, leaving KNO3 in solution; its solubility increases very little with temperature while KCl becomes significantly more soluble.
Similar questions