Question

Dps has 585 girl students and 1152 boy students. the school has sections based on their gender. all the sections have the same number of students. what are the minimum number of sections in the dps?

Answer 1

To work out this question we will need to find the greatest common divisor (GCD) of the number of girl students and the number of boy students:

GCD of 585 and 1152. This will give the number of students in each section.


The divisors of:

585 = 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585

1152 = 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 128, 144,                    192, 288, 384, 576, 1152

We can see from the list of the divisors of two numbers that the greatest common divisor is 9.

Therefore each section of DPS will have 9 students each.

The minimum number of sections therefore are :
 
The number of sections for the boys  = 1152/9 = 128 sections

The number of sections for the girls = 585/9 = 65 sections

Total number of sections = 128 + 65 = 193 sections

Therefore the minimum number of sections are 193 sections

Answer 2

Solution :-

We have to find the H.C.F of 585 and 1152

585 = 3*3*5*13

1152 = 2*2*2*2*2*2*2*3*3

Common factors = 3*3 

H.C.F. = 3*3 = 9

So, there are 9 sections in the school.

Answer