Question

DQ-8
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Multi Choice Type Question
Marks : 1 Negative Marks : 0
Given 3 different red dyes, 4 different blue dyes, and 5 different green
dyes, how many combinations of dyes can be made taking at least one
green and one blue dye?​

Answer 1

I don't think so the question is correct!

But I tried to answer it!!!

At. least one green dye can be selected out of 5 green dyes in 2

5

- 1, i.e. in 31 ways. Similarly at least one blue dye can be selected out of 4 in 2

4

- 1 in 15 ways. For red dyes there is no restriction; you may include it or not include it. Thus there are two ways of disposing of each of red dye. Thus the total number of selection of red dye is 2

3

= 8

. Hence the required number of ways 31 x 15 x 8 = 3720.