Question

Draw a ΔABC in which BC = 5 cm, AB = 4 cm and AC = 6cm​

Answer 1

Answer:

let AC be the base of 6cm.

Now with A as centre draw an arc of 4cm (AB).

With C as centre draw an arc of 5cm (BC).

The point where these two arcs intersect name it as B.

Join BA and BC.

Therefore ABC is the required triangle.