Question

Draw a ∆ abc , right angled at B such that AB = 3cm and BC = 4cm.Now construct a triangle similar to ABC , each of whose sides is 7/5 times the corresponding sides of ∆ABC
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Answer 1

Step-by-step explanation:

BQ=

5

7

BC=

5

28

=5.6

PB=

5

7

AB=

5

21

=4.2

On BA extended mark P at 4.2 cm from B on same side of A

On BC extended mark Q at 5.6 cm from B on same side of C

Join P,Q

∴△PBQ is formed.