Question

draw a circle of radius 3cm and take two points P and Q on its extended diameter each at distance of 7 cm away from the centre draw the triangle to the circle from this point P and Q​

Answer 1

this is your ans

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Answer 2

Answer:

Steps of Construction:

(a) Bisect PO. Let M be the mid-point of PO.

(b) Taking M as centre and MO as radius, draw a circle. Let it intersects the given circle at the points A and B.

(c) Join PA and PB. Then PA and PB are the required two tangents.

(d) Bisect QO. Let N be the mid-point of QO.(e) Taking N as centre and NO as radius, draw a circle. Let it intersects the given circle at the points C and D.

(f) Join QC and QD.

Then QC and QD are the required two tangents.

Justification:

Join OA and OB.

Then PAO is an angle in the semicircle and therefore ∠PAO = 90° .

PA ⊥ OA

Since OA is a radius of the given circle, PA has to be a tangent to the circle. Similarly, PB is also a tangent to the circle.

Again join OC and OD.

Then ∠QCO is an angle in the semicircle and therefore ∠QCO = 90° .

Since OC is a radius of the given circle, QC has to be a tangent to the circle. Similarly, QD is also a tangent to the circle.

Step-by-step explanation:

Hope this helps you ✌️