draw a circle of radius 4.9cm take a point K on it and draw tangent at K using centre of circle
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Step-by-step explanation:
Steps of Construction:Step I : Take a point O and draw a circle of radius 4.2 cm.Step II : Take a point P at a distance of 6.5 cm from the centre OStep III : Join OP and bisect it. Let M be the mid-point.Step IV : With M as centre and MP as radius draw a circle to intersect the circleat Q and R.Step V : Join PQ and PR. Then PQ and PR are the required tangents.On measuring we find PQ = PR = 4.9 cm.Justification:On joining OQ we find that ∠PQO = 90° as ∠PQO is the angle in the semicircle.∴ PQ ⊥ OQSince OQ is the radius of the given circle so PQ has to be atangent to the circle. Similarly PR is also a tangent to the circle.
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