Draw a circle of radius 5 cm. In the circle, draw a chord AB = 6 cm, then shade the minor and major
segments
AB= 5 cm, B = 60° and BC = 7 cm.
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Answer:
AC is the diameter of a circle with radius 5cm
AB=BC,CD=8cm,AC=10cm
Area of the circle =π(5)
2
=25π
Now, △ABC is a right angled triangle.
∴AC
2
=AB
2
+AC
2
....Pythagoras theorem
=>100=2AB
2
=>AB
2
=50
=>AB=
50
=>AB=5
2
∴AB=AC=5
2
Area of △ABC=
2
1
×AB×BC =
2
1
×5×
2
×5×
2
=25
Similarly,
△ADC is a right angled triangle.
∴AC
2
=AD
2
+DC
2
=>10
2
=AD
2
+8
2
=>100=AD
2
+64
=>AD
2
=36
=>AD=6
Area of △ADC=
2
1
×AD×DC=
2
1
×6×8=24cm
2
Area of shaded region =25π−25−24=25π−49=29.5cm
2
=30cm
2
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