Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangent to the circle and measure their lengths.
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but how we can draw sis
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Construct a circle with radius =6cm and centre be C
Locate a point A which is 10 cm from C
Then find the perpendicular bisector of line joining points C and A. lets say the mid point will be M.
Now draw an 'another circle with centre at M and radius =6cm(CA/2) and lets say this circle cuts the previous circle at
points N and Q then draw the lines AB and AN which are our external tangents.
Sinces △CSA is right angle triangle at L.S=90°
Therefore using pythagoras theorem
(CQ)2+(SN)2=(CA)2
(10)2−(6)2=(QN)2
QN=8cm is the length of the tangent.
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