Question

Draw a circuit diagram as described below. Connect two resistors R¹, and R²
, in parallel
and connect them with a battery ammeter and a plug key. Insert a voltmeter across
the resistors, show the direction of flow of current.
​

Answer 1

Draw a circuit diagram as described below. Connect two resistors R¹, and R²

, in parallel

and connect them with a battery ammeter and a plug key. Insert a voltmeter across

the resistors, show the direction of flow of current

Answer 2

Answer:    Here the circuit in which a resistor of resistance 4Ω is attached in series and two resistors of resistance 8Ω are attached in parallel. Also, Ammeter and voltmeter attached in the circuit in series and parallel respectively.

Now,  

Maximum power of each resistor is 16W  

4Ω resistor is joined in series with circuit .

so, Power=i  

2

R , here i is current through resistor of resistance R  

16=i  

2

∗4Ω

i = 2A  

Now, 2A is passing through parallel resistors of resistance 8Ω.

we know, in parallel potential difference be constant so,

current divides two part , due to same resistance current on each resistance will be half . so, current passing through each parallel resistor is  

2A

2

​  

=1A

So, finally current through 4Ω resistor =2A  

current through each 8Ω resistor =1A