draw a circuit diagram consisting of a battery of four cells each 2V,a 2 ohm resistor, 4 ohm resisitor and 6 ohm resistor , a plug key and an ammeter all connected in series. also connect a voltmeter across 6ohm resistor. also find the current flowing in the circuit and the potential difference across 6 ohm resisitor.
Answers
Answer:
0.5 ampere
Explanation:
Total resistance in circuit is 2+6+4=12 ohm
Voltage or potential difference=2+2+2=6 V
using ohm law V=I R
6= I *(12)
I=0.5 ampere
current in series resistance equals to total current in circuit
Given:
A circuit diagram consisting of a battery of four cells each 2V, a 2 ohm, 4 ohm and 6 ohm resistor, a plug key and an ammeter all connected in series.
Also connect a voltmeter across 6 ohm resistor.
To find:
Find the current flowing in the circuit and the potential difference across 6 ohm resistor.
Solution:
Consider the attached figure while going through the following steps.
The total/equivalent resistance = R = 2 + 4 + 6 = 12 Ω
The total/equivalent voltage = V = 4 × 2 = 8 V
The current in the circuit = I = V/R = 8/12 = 2/3 A
The voltage across 6 Ω resistance = V = I × R = 2/3 × 6 = 4 V
