Question

) Draw a circuit diagram showing a cell of 1.5V, a key, an ammeter,
two resistors of 2 Ω each connected in parallel, a resistor of 6 Ω in
series with the parallel combination and a voltmeter across the
parallel combination

Answer 1

Answer:

see the attachment please

Answer 2

Given that

• cell of 1.5V
• a key
• Ammeter
• Two resistors of 2Ω each connected in parallel
• voltmeter and a resistor of 6Ω

Solution

$</u><u>\bf \: Total \: resistance = \frac{1}{R_1} + \frac{1}{R_2} </u><u> \\ \\ \bf \: Total \: resistance = \frac{1} 2 + \frac{1} 2 </u><u> \\ \\ \bf \: Total \: resistance = 4$

potential differences V = 1.5 v

• current = I = ?

Applying ohm's law

$\qquad \sf \:V= IR \\ \\ \qquad \sf I = \frac{V}{R} \\ \\ \sf \: I = \frac{1.5}{3} \\ \\ \sf \: I = 0.5$

therefore Ammeter will show a reading of 0.5A