Question

Draw a graph of 2x+3y=12 on a graph paper .Find its point of intersection on x and y axis .Find the slope of the drawn graph.​

Answer 1

Answer and explanation:

The equation of line is  $2x+3y=12$

To draw the graph we find the x and y-intercept.

x-intercept when y=0,

$2x+3(0)=12$

$x=\frac{12}{2}$

$x=6$

Point is (6,0) which is intersection on x-axis.

y-intercept when x=0,

$2(0)+3y=12$

$y=\frac{12}{3}$

$y=4$

Point is (0,4) which is intersection on y-axis.

Refer the attached figure.

The slope form of line is $y=mx+c$ where m is the slope.

$2x+3y=12$

$3y=12-2x$

$y=-\frac{2}{3}x+4$

The slope is $m=-\frac{2}{3}$