Question

Draw a graph of a linear equation 2x + 3y=12.At what points ,the graph of the equation cuts the x-axis and y-axis?

Answer 1

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Answer 2

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : Linear equation $2x+3y=12$

To find : Draw a graph of a linear equation. At what points ,the graph of the equation cuts the x-axis and y-axis?

Solution :

The pointy where graph cut x-axis and y-axis are x-intercept and y-intercept.

The x-intercept is when y=0,

$2x+3(0)=12$

$2x=12$

$x=\frac{12}{2}$

$x=6$

So, Graph cut x-axis at (6,0).

The y-intercept is when x=0,

$2(0)+3y=12$

$3y=12$

$y=\frac{12}{3}$

$y=4$

So, Graph cut y-axis at (0,4).

Refer the attached figure for graph.