Draw a histogram and a frequency polygon from the following data
Class 21 - 25 ,26 - 30 ,31 - 35 ,36 - 40 ,41 - 45 ,46 - 50 ,51 - 55 ,56 - 60
Frequency 21 22 50 110 87 51 18 23
Answers
Step-by-step explanation:
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Answer:
the class intervals are equal but the series is inclusive one then the inclusive series are converted into exclusive series to have continuity in series.
Class Intervals Frequency
16 -20
4
21-25
12
26-30
18
31-35
26
36-40
14
41-45
10
46-50
6
Procedure to convert the inclusive series into the exclusive series:
Calculate the difference between the upper limit of the class interval and the lower limit of the next class interval, i.e. 20 – 21 = 1.
Half of the difference value is added to the upper limit of the class interval and half of the difference value is deducted from the lower limit of the class interval.
Exclusive series of the given inclusive series as follows:
Class Intervals Frequency
15.5-20.5
4
20.5-25.5
12
25.5-30.5
18
30.5-35.5
26
35.5-40.5
14
40.5-45.5
10
45.5-50.5
6