Question

Draw a line EF and take a point P above EF. Draw a line GH passing through p such that GH//EF​

Answer 1

Step-by-step explanation:

suppose you take EF and the point p above it

suppose you take EF and the point p above it draw a perpendicular bisector from p to EF at M

suppose you take EF and the point p above it draw a perpendicular bisector from p to EF at Mextend ray PM in vertical direction

suppose you take EF and the point p above it draw a perpendicular bisector from p to EF at Mextend ray PM in vertical direction then draw perpendicular bisector of it . Name it GH and it will be parallel it EF as ray PM is perpendicular to both lines . Therefore EF is // to GH