draw a line segement pq of lenght 7cm and find a point ron it such that pr:rq=2:3
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Step-by-step explanation:
3:5 => 3+5 = 8 Therefore A1 A2 A3 A4 A5 A6 A7 A8
Construction:
1. Draw a line segment AB = 7cm.
2. Draw /_ BAX which is acute angle
3. Cut A A1 = A1 = A2, A2 = A3, A3, A4, ......A7=A8.
4. Draw /_ A A8 B = /_ A A3 P
5. P is the rejected point that divides AB in the ratio 3:5
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