Question

Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From the point P, draw a perpendicular to AB.

#Math
#Class 8th [ICSE]
#Page no. 195

Answer 1

QUESTION ----- Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From the point P, draw a perpendicular to AB.

ANSWER
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Steps for Construction :

* Draw a line AB = 5.5 cm

* Taking Point A as radius take radius of 6 cm on Compass and draw an arc

* Now taking Point B as centre take radius 4.8 cm and draw an arc.

*The point at which the two arcs meet is Point P

* Now taking point P take radius of any suitable and draw a semi circle

*Draw a line parallel to AB from point P

* Draw 90° angle on the above drawn line from Point P.

* This will meet AB at a point and form 90° with it also because if one angle between two parallel lines cut by a transversal is 90° then all interior angles = 90°.


HENCE, YOU WILL DRAW THE REQUIRED FIGURE.

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HOPE IT HELPS :):):):):)

Answer 2

Answer:-

Steps for Construction :

* Draw a line AB = 5.5 cm

* Taking Point A as radius take radius of 6 cm on Compass and draw an arc

* Now taking Point B as centre take radius 4.8 cm and draw an arc.

*The point at which the two arcs meet is Point P

* Now taking point P take radius of any suitable and draw a semi circle

*Draw a line parallel to AB from point P

* Draw 90° angle on the above drawn line from Point P.

* This will meet AB at a point and form 90° with it also because if one angle between two parallel lines cut by a transversal is 90° then all interior angles = 90°.

HENCE, ABCD IS A REQUIRED QUADRILATERAL.