draw a line segment AB =5cm .at A, draw AD∆AB ,such that DC = 5cm and parallel to AB . now join CB . measure ∆ABC,∆BCD and length of BC . is figure ABCD a rectangle.
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Here the length of AB = 5cm
DA is perpendicular to AB.
EB is perpendicular to AB.
Two lines perpendicular to the same line are always parallel to each other.
Also ∠1 =∠ 3 = 90°
So ∠1 + ∠3 = 180°
If the sum of co interior angles = 180°, the lines are parallel.
Hence AD || BE
Now we construct the perpendicular bisector of AB which intersects AB at C
Again
∠1= ∠2 = 90°
So
∠1 + ∠2 = 180°
We know If the sum of co interior angles = 180°, the lines are parallel.
Hence AD || CF
Now BE ||AD || CF
Hence all the three lines are parallel to each other.
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