Math, asked by avnimaheshwari0, 1 month ago

draw a line segment AB = 6.8 cm and draw a perpendicular at a point P on it​

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Answered by 919925023197
2

Step-by-step explanation:

1.Draw a line AB=6.8cm. Taking A as center, and radius more than

2

1

AB,draw arcs on top and bottom of AB

2.Taking A as center, and radius as before,draw arcs on top and bottom of AB

3.Let the point where arcs intersect on top of AB be P.And the point where arcs intersect at the bottom be Q.Join PQ

4.Let PQ intersect AB at the point M.

Thus, line PMQ is the required perpendicular bisector of AB.

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