Question

If tan alpha = 2/5 , find the numerical value of (sin alpha - 2cos alpha)/(cos alpha - 3sin alpha)​

Answer 1

Step-by-step explanation:

We have,

5 tan α⇒tanα=

5

4

Now,

5sinα+2cosα

5sinα−3cosα

=

cosα

5sinα+2cosα

cosα

5sinα−3cosα

=

cosα

5sinα

+

cosα

2cosα

cosα

5sinα

−

cosα

3cosα

=

5tan,α+2

5tan,α−3

=

5×

5

4

+2

5×

5

4

−3

=

4+2

4−3

=

6

1