Math, asked by shaiknadiyaapsb, 22 hours ago

Draw a line segment AB=6 cm and divide it in the ratio 3:1 . Prove that the perpendicular is parallel to the line segment. ​

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Answered by adityashewale368
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Draw a line segment of 6cm and divide it in the ratio 3:2.

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Let the line segment be PQ

Now we will divide the line segment PQ with ratio 3:2

Step 1: Firstly we will draw a line 6cm PQ.

Step 2: Draw any other ray PX, makes angle less than 90 (acute angle).

Step 3: Mark the 5 (because 3 + 2 = 5) arcs in a line PX, named P₁, P₂, P₃, P₄, P₅.

such that,

PP₁ = P₁P₂ = P₂P₃ = P₃P₄ = P₄P₅

Step 4: Join QP₅.

Step 5: Draw a parallel line QP₅ from P₃. That is intersect the PQ line at point R.

Answered by navithukulasekara
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