Draw a line segment AB equal to 9 cm. Using compasses and ruler, construct its
perpendicular bisector.
Answers
Answer:
._________________.
A. 9cm B
Step-by-step explanation:
#1. Draw a line segment AB of length 9cm.
<-----•--------------------------•------>
A 9cm B
#2. Take 9cm distance in rounder (compass) and keep the pointer on point A and draw an arc in the area above the the line segment.
#3. Don't change the distance and keep the pointer on point B and draw an arc that intersects the previous arc ( drawn in step #2).
•P (point of intersection of both arcs)
<-----•--------------------------•------>
A 9cm B
#4. follow the sreps #2 & #3 again and draw the arcs but in the area below the line segment.
•P (point of intersection of both arcs)
arcs)<---•--------------------------•---->
arcs)<---•--------------------------•----> A 9cm B
•Q(point of intersection of both arcs)
#5 join the points P and Q and a verticle line will be formed name it as ' m '.
draw an arrow here
|
|
•P
|
|
|
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| mark 90°and mark angle as M
<---•------------------------•---->
<---•------------------------•----> A | 9cm B
l
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•Q
|
| draw an arrow
mark this line as ' m '
Therefore line ' m ' is a perpendicular bisector of segAB
[Note: that length of PM and length of MQ will be equal & MA and MB will also be equal]