Question

draw a line segment of length 7 cm.find a point p on it which divides it in the ratio 3:5​

Answer 1

Answer:

Draw a line segment AB=7 cm.

2. Draw a ray AX , making an acute ∠BAX∠BAX.

3. Along AX, mark 3+5=8 points

A1,A2,A3,A4,A5,A6,A6,A7,A8A1,A2,A3,A4,A5,A6,A6,A7,A8 such that

AA1=A1A2=A2A3=A3A4=A4A5=A5A6=A6A7=A7A8AA1=A1A2=A2A3=A3A4=A4A5=A5A6=A6A7=A7A8

4. Join A8BA8B.

From A3A3, draw A3C∣∣A8A3C∣∣A8 B meeting AB at C. [ by making an angle equal to ∠BA8A at A3∠BA8A at A3]

Then, C is the point on AB which divides it in the ratio 3:5.

Thus, AC:CB=3:5



Justification

Let AA1=A1A2=A