Draw a line segment of the length 5cm and draw perpendicular bisect
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A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of the original line segment.
Take any point on the perpendicular bisector and join it with the ends of the line segment considered. Then the line segments thus formed are equal.
Consider the figure,
AB is the base, MP is the perpendicular bisector to AB
Join PA and BP
In triangles AMP and PMB
AM=MB
∠AMP=∠PMB=90
∘
PM is the common side
From SAS postulate, the triangles are congruent. Hence, the third sides are also equal.
i.e., AP=BP.
Step-by-step explanation:
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