Question

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Question :

The total surface area of a rectangular block of wood is 6048 cm^2. If the area of its square base is 1296 cm^2.Find its height.

#Urgently needed

Answer 1

Tsa= 2(lb+bh+hl)

=6048

lSA= 2(l+b)h

=1296

2lb+2bh+2hl=6048

1296+lb=6048

lb= 6o48-1296

= 4 76 2

in case of square base

l= b

l^2=4762

now put the value of l, b in TSA

and get height...

I think help u....

Answer 2

Let the height be h

We are given that the base is square, hence l = b

Given that area of square base is 1296

→ l² = b² = 1296 cm²

(since, area of square = side²)

→ l = b = √1296

→ l = b = 36 cm

Now, given that total surface area = 6048

We know that total surface area of cuboid = 2(lb + bh + lh)

substituting the values of l and b and equating, we get

2(36 × 36 + 36h + 36h) = 6048

→2(1296 + 72h) = 6048

→ 2592 + 144h = 6048

→ 144h = 6048 - 2592

→ 144h = 3456

→ h = 3456/144

→ h = 24 cm

Hence, the height of the given rectangular block is 24 cm