Math, asked by gunjanjangir, 1 year ago

Draw a line segment pq. Take a point M on it such that PM=MQ . draw MN\Pq

Answers

Answered by guptasingh4564
10

As shown in the figure MN\parallel PQ and MN\parallel PQ

Step-by-step explanation:

Given,

Draw a line segment PQ. Take a point M on it such that MN\parallel PQPM=MQ  and draw MN\parallel PQ

Following steps:

  • Draw a any line segments PQ using scale.
  • At P\ and\ Q, draw angle 45\ degree such that \angle QPX=45\ degree\ and\ \angle PQY=45\ degree
  • Line PX\ and\ QY intersect at M where PM=MQ
  • Draw perpendicular line on PQ through point M which intersect the line PQ at O
  • At M, draw an angle 90\ degree using setsquare such that MN\parallel PQ

Hence, As shown in the figure MN\parallel PQ and MN\parallel PQ

Attachments:
Answered by Rohitchambile
0

Step-by-step explanation:

As shown in the figure MN\parallel PQMN∥PQ and MN\parallel PQMN∥PQ

Step-by-step explanation:

Given,

Draw a line segment PQPQ . Take a point MM on it such that MN\parallel PQMN∥PQ PM=MQPM=MQ and draw MN\parallel PQMN∥PQ

Following steps:

Draw a any line segments PQPQ using scale.

At P\ and\ QP and Q , draw angle 45\ degree45 degree such that \angle QPX=45\ degree\ and\ \angle PQY=45\ degree∠QPX=45 degree and ∠PQY=45 degree

Line PX\ and\ QYPX and QY intersect at MM where PM=MQPM=MQ

Draw perpendicular line on PQPQ through point MM which intersect the line PQPQ at OO

At MM , draw an angle 90\ degree90 degree using setsquare such that MN\parallel PQMN∥PQ

Hence, As shown in the figure MN\parallel PQMN∥PQ and MN\parallel PQMN∥PQ

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