Sum of the 3 terms of A.P. is 36 and product is 1296. Find A.P.
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Answered by
1
a+d=0
a+2d=36
3d=36
d=12
a=36-24
a=12
a+2d=36
3d=36
d=12
a=36-24
a=12
Answered by
2
Let the AP be a+d,a,a-d.
a+d+a+a-d=36
=3a=36
=a=36/3=12.
AP=a-d,a,a+d
Given:
(a-d)(a+d)*a=1296
=(12-d)*(12+d)=1296/12
=144-d²=108
=-d²=-36
=d²=36
=d=6
AP=12-6,12,12+6
=6,12,18
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