Draw a line through the point (−2,2) with a slope of −3. Draw a line through the point (2,−2) with a slope of −3.
Answers
why you wrote question 2 times
Step-by-step explanation:
its like teacher give punishment like write this thing 10 or 20 times lol
Concept:
The equation of a straight line with slope ' m ' which passes through the point (a,b) is given by,
(y - b) = m (x - a)
Given:
Given a straight line passes through the point (-2,2) and the slope of it is -3.
Find:
We have to draw a line on graph which with above given conditions.
Solution:
Given the slope of the straight line is -3.
And the line passes through the point (-2,2)
So here, m = -3; a = -2; b = 2
Thus the equation of the straight line is,
(y - 2) = -3 (x - (-2))
y - 2 = - 3 (x + 2)
y - 2 = -3x - 6
3x + y - 2 + 6 = 0
3x + y + 4 = 0
So the straight line cuts the X axis and Y axis at (-4/3,0) and (0,-4) respectively.
Hence the graph of the given straight line which passes through (-2,2) with slope -3 i.e. the straight line with equation 3x + y + 4 = 0 is,
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