Question

draw a ∆PQR such that QR = 5cm PQ =4cm and PR 2.5 cm​

Answer 1

Answer:

answer hope it helps please mark as brainliest

Explanation:

1. Draw a line segment QR of length 3cm.

2. Now, we draw 95

o

degrees from point Q.

3. Taking Q as centre, 5cm radius, we draw an arc. Let the point where arc intersects the ray be point p.

4. Joint PR and label the sides.

Thus, PQR is the required triangle.

solution