Question

Draw a rhombus ABCD in which diagonals
AC = 4.5 cm and BD=6 cm.
Suppose the two diagonals of this rhombus are equal in length , what figure did you obtain . Draw a rough sketch for it .State reasons.​

Answer 1

Step-by-step explanation:

Given: One diagonal of rhombus ABCD is 5.5 cm and side is 4.5 cm.

All the sides of a rhombus are equal in length. So, l(AB)=4.5 cm, l(BC)=4.5 cm, l(CD)=4.5 cm and l(DA)=4.5 cm

Let the given diagonal is AC = 5.5 cm

Steps of Construction:

(1) Draw diagonal AC = 5.5 cm.

(2) Then, draw an arc taking A as centre and 4.5 cm as the radius. Now, draw another arc with C as the centre and 4.5 cm as the radius, cutting the previous arc at D. Then, join AD and DC.

(3) Draw an arc on the opposite side of D by taking A as centre and 4.5 cm as the radius. Then, draw another arc with C as the centre and 4.5 cm as the radius, cutting the previous arc at B. Then, join BC and AB.

Thus, ABCD is the required rhombus.

I hope it's helpful for you.

Answer 2

Answer:

rhombus

Step-by-step explanation:

draw diagonal AC=4.5 CM as base

draw an arc by taking A as centre and 4.5cm as the radius

draw another arc with c as the centre and 4.5 CM as the radius. cutting the previous arc at D

then join AD and DC

draw an arc on the opposite side of D by taking A as centre and 4.5cm as the radius then draw another arc with C as the centre and 4.5 CM as the radius, cutting the previous arc at B

Thus ABCD is the required rhombus