Question

Draw a rhombus with side 3.5 cm and one of its angles is 45°​

Answer 1

Answer:

1. Take AB = 3.5cm.

2. At A and B , construct ∠ BAM = 45 ∘  and ∠ TBP = 45 ∘  respectively which are bisectors of 90 .To draw bisector of ∠ALB take suitable radius and make arc on AB and AL with same radius. Again take radius more than half of previous radius and make arcs from previous points on AL and AB. Joining this new point of contact of arcs and A will give bisector of LAB.

Similarly we draw 45 ∘ at point B

3. From AM cut off AD = 3.5cm and from BP cut off BC = 3.5cm.

4. Join AD , DC and BC . ABCD is the required rhombus.

Step-by-step explanation:

Answer 2

Step 1 : Draw a line segment AB of 3.4 cm. Step 2 : At, B construct an angle ABC of 45°. Step 3 : Cut off BC = 3.4 cm on ray BO. Step 4 : With A as center and radius 3.4 cm draw an arc above A