draw a right triangle in which the side are of the length 4cm and 3cm.then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle.
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hey .. firstly draw a line segment AB = 3cm
then 90° on angle A and from point B draw a line of 4cm at C
after that make any acute angle on A and cut 5 equal arcs . Join A3B and make A5B' parallel to A3B .And make B'C' parallel to BC .
AB'C' is the required triangle .....
hope it will help ..
and plzz mark as brainliest ....
then 90° on angle A and from point B draw a line of 4cm at C
after that make any acute angle on A and cut 5 equal arcs . Join A3B and make A5B' parallel to A3B .And make B'C' parallel to BC .
AB'C' is the required triangle .....
hope it will help ..
and plzz mark as brainliest ....
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