Draw a right triangle in which the sides (other than hypotenuse) are of lengths 8cm and 6cm , then construct another triangle whose are 5/3 times the corresponding sides of the given triangle
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Step-by-step explanation:
Steps of constructions :
1. Draw a line segment BC = 8 cm.
2. Draw line segment BX making an angle of 90º at the point B of BC.
3. From B mark an arc on BX at a distance of 6 cm, Let it is A.
4. Join A to C.
5. Making an acute angle draw a line segment BY from B.
6. Mark B1, B2, B3, B4 on BX such that BB1 = B1B2 = B2B3 = B3B4.
7. Join B4 to C.
8. Draw a line segment B3C' || to B4C to meet BC at C'.
9. Draw line segment CA' || to CA to meet AB at A' A'BC' is the required triangle.
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